Assignment #5 - 88B

                                           T.A. HARRIS PARASKEVAS
                                                DUE: NOV  12
                                                WEIGHT: 25
                     Assignment 5
                   CABLE CAR VELOCITY
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 THIS PROBLEM INVOLVES A 1000-FOOT CABLE THAT IS STRETCHED BETWEEN TWO
TOWERS WITH A SUPPORTING TOWER MIDWAY BETWEEN THE TWO END TOWERS. THE
VELOCITY    OF THE CABLE CAR DEPENDS ON ITS POSITION ON THE CABLE. WHEN
THE CABLE CAR IS WITHIN 30 FEET OF A TOWER, ITS VELOCITY IS:

             VELOCITY = 2.425 + 0.00175*D*D FT/SEC

WHERE D IS THE DISTANCE IN FEET FROM THE CABLE CAR TO THE NEAREST
TOWER. IF THE CABLE CAR IS NOT WITHIN 30 FEET OF A TOWER, ITS
VELOCITY IS:

             VELOCITY = 0.625 + 0.12*D - 0.00025*D*D FT/SEC

 PRINT THE TABLE STARTING WITH THE CABLE CAR AT THE FIRST TOWER
AND MOVING TO THE LAST TOWER IN INCREMENTS OF 10 FEET. AT EACH
INCREMENT OF 10 FEET, PRINT THE NUMBER OF THE NEAREST TOWER
(1 = FIRST, 2 = SECOND, 3 = END), THE DISTANCE FROM THE FIRST
TOWER, AND THE VELOCITY OF THE CABLE CAR.